计算给定dir的.php文件中的所有代码行

Question

How to make a little function that given a directory it returns the number of lines (counts ) of .php files between <?php and ?>?

Usage:

echo countsLineOfCode('D:/dir/code/');    
// returns 323;

Answer 1

function countLinesOfCode($path) {
   $lines = 0;
   $items = glob(rtrim($path, '/') . '/*');

   foreach($items as $item) {

       if (is_file($item) AND pathinfo($item, PATHINFO_EXTENSION) == 'php') {
           $fileContents = file_get_contents($item);
           preg_match_all('/<\?(?:php)?(.*?)($|\?>)/s', $fileContents, $matches);

           foreach($matches[1] as $match) {
               $lines += substr_count($match, PHP_EOL);
           }

       } else if (is_dir($item)) {
           $lines += countLinesOfCode($item);
           continue;
       }       

   }

   return $lines;
}

var_dump(countLinesOfCode(dirname(__FILE__))); // int(31) (works for me)

Keep in mine this is counting newlines, not end of line character ;. For example, the line below will be considered one line...

var_dump($files); echo 'something'; exit;

It also counts lines without any PHP code, e.g. the below code will be 4 lines...

<?php



$a = 3;

It also doesn't count the <?php or closing (if present).

Let me know if it (a) shouldn't match empty lines, (b) should match semi colons instead (will need to ensure they are not appearing within a string) and/or (c) it should match the opening and closing tag (will be easy as changing $matches[1] in the foreach to $matches[0]).