使用regex查找bin编号中的二进制间隔

Question

I want to catch all binary gaps in bin number with regex. For example if I have 1010010001 I want to get array of these 3 strings: "0", "00", "000" but my regex doesn't use 3-rd "1" for both "101" and "1001" combinations. Here is my regex:

/1(0+)1/g

How I should modify my regex to get desired result ?

Answer 1

You need to make sure the trailing 1 is not consumed by putting it into a positive lookahead:

/1(0+)(?=1)/
      ^^^^^

See the regex demo.

A matching variation of the same pattern:

/1\K0+(?=1)/

Here, 1 matches 1 and this text is omitted with \K, then one or more 0s are matched and 1 presence is checked after the 0s.