更正PHP中文件上载字段的变量引用

Question

I am trying to successfully use the PHP empty() function. Currently my script references the input file field variable:

<input  class="fileUpload" name="flyer" type="file"  />

like this:

if (empty($_FILES['flyer']['name'])) {
//don't update the file 
}
else {
//update the file url
}

This currently updates the file URL to a value of null if it's empty. The problem could be something else but I think it's my variable reference. How can I correct this to get the empty function to work?

Answer 1

if it is a FILE type then you need to use the $_FILES[-name-]['error'] handler to check the quality of file, check http://php.net/manual/en/features.file-upload.errors.php

Ignore the name value, what you want is

if ($_FILES['flyer']['error'] == 4) {
//// this file given was empty. 
}