douwen3836 2014-02-16 10:41
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PHP / MySQL:获取一个结果

This is my database:

database

This is the query:

SELECT * FROM users

Now when I do this:

$query = $connection->query($_GET['query']); // SELECT * FROM users
print_r($query->fetch_assoc());

I get this as output:

Array ( [id] => 3 [username] => karel )

Why does it not output id 4 and username ccscs?

When I a while loop:

whileloop

while($row = $query->fetch_assoc()){
    print_r($row);
}
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3条回答 默认 最新

  • dpj775835868 2014-02-16 10:45
    关注

    This is happening because you don't give any order to your query so it automatically get first record. If you want to return last record you can order by id desc as follow

    SELECT * FROM users ORDER BY id DESC
    

    If you instead need to retrieve all records you will need to loop throw your records

    while($row = $query->fetch_assoc())
    {
        print_r($row);
    }
    

    Based on new op info i would not fetch twice but one as follow

    $fields = array();
    while($row = $query->fetch_assoc())
    {
        print_r($row);
        $fields[] = $row;
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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