如何在php中获取图像alt =“...”的值？

Question

hi all i got many sets of data show below(in $code variable). i wonder how i can output all values of image alt="..." ? For example i want to get : Music Club ( sun ) Music 09

from:

        <img src="http://www.example.com/teststorage/episodes/11224/201.jpg" alt="Music Club ( sun ) Music 09" />

sample set of data:

    <div class="col-lg-3 col-md-3 col-sm-6 col-xs-12 item">
        <div class="portfolio-item">
            <a href="http://www.example.com/en/test/1234/11224/Music 09" title="Music Club ( sun ) Music 09" class="portfolio-item-link" >
                <span class="portfolio-item-hover"></span>
                <span class="fullscreen"><i class="icon-play"></i></span>
                <img src="http://www.example.com/teststorage/episodes/11224/201.jpg" alt="Music Club ( sun ) Music 09" />
            </a>
            <div class="portfolio-item-title">
                <a href="http://www.example.com/en/test/1234/11224/Music 09" title="Music Club ( sun ) Music 09" class="portfolio-item-link"><h4>Music 09</h4></a>
            </div>
            <div class="clearfix"></div>
        </div>
    </div>

Answer 1

If you realy want to use preg_match_all you could use the following code.

<?php
$str = <<<END
<div class="col-lg-3 col-md-3 col-sm-6 col-xs-12 item">
        <div class="portfolio-item">
            <a href="http://www.example.com/en/test/1234/11224/Music 09" title="Music Club ( sun ) Music 09" class="portfolio-item-link" >
                <span class="portfolio-item-hover"></span>
                <span class="fullscreen"><i class="icon-play"></i></span>
                <img src="http://www.example.com/teststorage/episodes/11224/201.jpg" alt="Music Club ( sun ) Music 09" />
            </a>
            <div class="portfolio-item-title">
                <a href="http://www.example.com/en/test/1234/11224/Music 09" title="Music Club ( sun ) Music 09" class="portfolio-item-link"><h4>Music 09</h4></a>
            </div>
            <div class="clearfix"></div>
        </div>
    </div>
END;

preg_match_all('/<img(.*?)alt=\"(.*?)\"(.*?)>/si', $str, $out, PREG_SET_ORDER);

//see first output
var_dump($out);

/*
array(1) {
  [0]=>
  array(4) {
    [0]=>
    string(105) "<img src="http://www.example.com/teststorage/episodes/11224/201.jpg" alt="Music Club ( sun ) Music 09" />"
    [1]=>
    string(65) " src="http://www.example.com/teststorage/episodes/11224/201.jpg" "
    [2]=>
    string(27) "Music Club ( sun ) Music 09"
    [3]=>
    string(2) " /"
  }
}
*/

//clean array
$alt = array();

foreach($out as $val) {
  $alt[] =  $val[2];
}

//see cleaned output
var_dump($alt);
/*
array(1) {
  [0]=>
  string(27) "Music Club ( sun ) Music 09"
}
*/
?>

If you want to do the right thing however, I would look into simple_html_dom. You can do something like:

<?php
// Create DOM from URL or file
$html = file_get_html('http://www.example.com/page_i_want_to_spider.php');

// Find all images
foreach($html->find('img') as $element)
       echo $element->alt . '<br>';
?>