无法执行变量php中返回的函数

Question

I have a function with this syntaxe :

$variable = function() {
    return function(){
        //code
    }
}

I can't execute that function with

$variable()

Is there a way to execute this function ?

Answer 1

I don't know for what is it... But here example:

$a = function () {
   return function () { 
       return 1; 
   };
};
$b = $a();
echo $b();