将数组转换为另一种格式（PHP）

Question

i want to convert this array

 Array
(
    [2] => Array
        (
        )
    [4] => Array
        (
            [12] => Array
                (
                )
            [13] => Array
                (
                 [16] => Array
                    (
                    )
                )
        )
    [5] => Array
        (
        )
    [10] => Array
        (
        )
    [14] => Array
        (
        )
)

into this format

Array
(
    [2] => 2
    [4] => Array
        (
            [0] => 12
            [13] => Array
                (
                    [0] => 16
                )
        )

    [5] => 5
    [10] => 10
    [14] => 14
)

can anybody help? thanks. [continued 16Mar2010]

its not

[2] =>array

but

[2] => 2

if it is an array with 1 child or more, then it would be [4] => Array([12]=>12

input data is

$a = array(2 => array(), 4 => array(12 => array(), 13 => array(16 => array())), 5 => array(), 10 => array(), 14 => array());

Answer 1

function refactor($a){
  $result = array();
  foreach($a as $k => $v)
    $result[$k] = (is_array($v) && count($v) > 0) ? refactor($v) : $k;
  return $result;
}

$a = array(2 => array(), 4 => array(12 => array(), 13 => array()), 5 => array(), 10 => array(), 14 => array()); print_r($a); $b = refactor($a); print_r($b);

Sorry, didn't see that you wanted the internal array not to have the keys and values as the same.

EDIT: After you updated your question, I edited my function to do what you need:

function refactor($a, $rootNode = false){
  $result = array();
  foreach($a as $k => $v){
      if($rootNode){
          $result[$k] = (is_array($v) && count($v) > 0) ? refactor($v) : $k;
      }else{
          $result[] = (is_array($v) && count($v) > 0) ? refactor($v) : $k;      
      }
  }
  return $result;
}

$a = array(2 => array(), 4 => array(12 => array(), 13 => array(16 => array())), 5 => array(), 10 => array(), 14 => array());
print_r($a);
$b = refactor($a, true);
print_r($b);