PHP中的年份比较

Question

        if($_POST['syear']){
            $compy = strtotime($_POST['syear']);
            if(date("Y") <= date("Y", $compy)){
                //success
                $startdate = $_POST['syear'];
            }
            else{
                $error = 6;
            }
        }

I have created the above code and have no idea where I have gone wrong. I am posting a string from a form with a number in it and want to compare it to the current year. If the number is equal to or less than the current year it is supposed to be a success. It is always a success even if the number is larger than the current year. Do I need to convert some strings to ints or have I missed something entirely.

Answer 1

PHP handle string comparison very well, did you try this directly ? (and changing the comparison order to >=)

if($_POST['syear']){
    if(date("Y") >= $_POST['syear']){
        $startdate = $_POST['syear'];
    }else{
        $error = 6;
    }
}