Python正则匹配

Question

从字符串11111111112222222找出第二个1，与第三个2之间的字符串

Answer 1

正则匹配可以使用re库，代码如下：

import re

string = "11111111112222222"

# 查找第二个1的索引
one_matches = re.finditer("1", string)
one_match_indices = [m.start() for m in one_matches]
one_index2 = one_match_indices[1]

# 查找第三个2的索引
two_matches = re.finditer("2", string)
two_match_indices = [m.start() for m in two_matches]
two_index3 = two_match_indices[2]

# 提取子字符串
result = string[one_index2 + 1:two_index3]
print(result)

运行结果：

码字不易，有用希望点个采纳哦！