为什么echo与printf结合显示输出错误？

Question

Does anyone know why when I execute this :

#!/usr/bin/php
<?php

$eff_theo = array_fill(0, 10, 100);

for ($i = 0; $i < 10; ++$i)
   echo printf("%5d", $eff_theo[$i]).' ';
echo PHP_EOL;
?>

I get this :

1005 1005 1005 1005 1005 1005 ...

Answer 1

You're mixing echo and printf.

printf returns the length of the formatted string, so your echo call is printing out '5'.

Try removing the echo and try it again....