如何在php判断调节后插入一个弹出框?

Question

php判断所有数据存在后,想要弹出一个弹出框告诉已经填写数据成功.这个应该怎么加加进去?

if ($_POST["COMPANY"]){
                        echo '<script language="javascript"></script>';
                    }
                    ?>

想要在这里面加一个自己写的js弹出框应该怎么加?

 var trial = new trialpop()
    $('#subscribe').bind('click',function(){
        trial.subscribe({
            title:'',
            btn:'x',
            message:'',
            confirm:function(){
                window .open("")
            },
        })
    })
    function trialpop(){
        var _this = this;
        _this.subscribe = function(obj){
            var qback = $('<div class="qback"></div>')
            var confirmBox = $('<div class="alertBox"></div>')
            var confirmHead = $('<div class="alertHead">'+obj.title+'</div>')
            var confirmBack = $('<div class="closebtn">'+obj.btn+'</div>').on('click',function () {
                qback.remove()
                confirmBox.remove()
            })
            var confirmMes = $('<div class="alertMes">'+obj.message+'</div>')
            var confirmBtn = $('<span class="ConBtn">パス①</span>').on('click',function(){
                qback.remove()
                confirmBox.remove()
                setTimeout(function(){
                    obj.confirm()
                },100)
            })
            confirmBox.append(confirmBack);
            confirmBox.append(confirmHead);
            confirmBox.append(confirmMes);
            confirmBox.append(confirmBtn);
            qback.append(confirmBox);
            $('body').append(qback);
            confirmBox.css({'marginTop':-confirmBox.outerHeight()/2+'px'});
        }}
</script>

Answer 1

https://bbs.csdn.net/topics/390042537