我有网页网址列表，我只需要使用正则表达式从中删除除特定值和ID之外的所有内容

Question

Suppose I have list of URLs that follow structure below. I need to strip each one out so all thats left is the abcustomerid=12345. How can I do this using regex with notepad ++?

Here's an example of the different variety in each line. I just need to remove everything from each line, but leave the abcustomerid=12345 or whatever value that follows abcustomerid.

/the/stucture/blah.php?timeout=300&abcustomerid=53122&customer=zxyi
/some/other/struct/pagehere.php?today=Thursday&abcustomerid=241&count=54
/blah/blah/tendid.php?abcustomerid=12525

Each line could have anything different around the abcustomerid, but i just need to remove everything and keep the abcustomerid and the value.

Answer 1

This regex should do it.

(?:&|\?)abcustomerid=(\d+)

Usage:

<?php
$string= '/the/stucture/blah.php?timeout=300&abcustomerid=53122&customer=zxyi
/some/other/struct/pagehere.php?today=Thursday&abcustomerid=241&count=54
/blah/blah/tendid.php?abcustomerid=12525';
preg_match_all('~(?:&|\?)abcustomerid=(\d+)~', $string, $output);
print_r($output[1]);

The ?: tells the regex not to capture that group. We don't want to capture that data because it is irrelevant. The () capture the data we are interested in. The \d+ is one or more numbers (the + is the one or more part of it). If it can be any value change that to .+? which will match anything but then you will need an anchor for where it should stop. I'd use (?:&|$), which tells it to capture until the next & or the end of the string if it is multilined you'll need to use the m modifier. http://php.net/manual/en/reference.pcre.pattern.modifiers.php

Output:

Array
(
    [0] => 53122
    [1] => 241
    [2] => 12525
)

Demo: http://sandbox.onlinephpfunctions.com/code/37a4ddea8c50f98a41ac7d45fec98f5f1f58761f