json_encode与PHP 5.1.6和jQuery

Question

PHP5.1.6 has no json_encode(), so I wanted to use function found on json_encode documentation. I am trying to use output of this function with ajax request:

fetchArticles: function( e ) {
      $.ajax({
        url: 'article.php',
        type: 'POST',
        data:  { id: $(this).data( 'id_prod' ) },
        dataType: 'json',
        success: function( results ) {
          console.log('finished');
          console.log(results);
        }
      });

In article.php I have at this time:

if ( isset($_POST['id']) ) {
 connect();
 $articles = get_articles( $_POST['id'] );
 echo json_encode( $articles ); return;
}

The problem is with returning results to JS console:

• if there is no results, empty array is printed,
• if there is one results, proper object is printed,
• but when there is more than one result nothing is being printed to console, not even word finished.

I can see in HTTP headers and responses that proper data is returned, but it is not printed to console. Could you help me with solving this problem?

Answer 1

When the json file can't be converted it throws parsererror exception, so try this:

  $.ajax({
    url: 'article.php',
    type: 'POST',
    data:  { id: $(this).data( 'id_prod' ) },
    dataType: 'json',
    success: function( results ) {
      console.log('finished');
      console.log(results);
    },
    error: function(jqXHR, textStatus, errorThrown) { 
      console.debug(jqXHR, textStatus, errorThrown); 
    }
  });

It will output your error when the JSON is invalid.