PHP代码打破调用require函数

Question

I have a code snippet as follows

echo "calling require";
require ('../includes/functions/database.php');
echo 'require called';

my code echoes the first command and prints "Calling required."

as soon as it hits require function my code breaks and does not execute any further, as a result I don't get to print the last echo "require called"

What could be the possible reason?

Answer 1

The file may exist but may be unreadable. Use is_readable() to check it:

if(is_readable('../includes/functions/database.php')) {
   echo('ok!');
}

Also, there may be an error or die() inside database.php file which prevents further execution. Check database.php for errors and die / exit calls.

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Add error_reporting(E_ALL); ini_set('display_errors', 'On'); at the beginning of your scipt to debug errors as Salman A suggested in the comments.