doudiecai1572 2012-07-16 23:09
浏览 22
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表单不会在IE9中发布选择值

All, I've got the following page: http://tinyurl.com/7lzr6qo

The original form code is:

<form id="dj_feedback" name="dj_feedback" action="../test-save-feedback" method="post">
<br>
<h2>How was the Event?</h2>
<hr>
<table><tr><td width="100px" valign="middle">
<b>Person<font color="#FF0000"> * </font></b>
</td><td valign="middle">
<select name="dj_name" id="dj_name">
<option value="original"></option>
<?php
$qrydj = "Select user_id, first_name, last_name from users where role='employee'";
$resultdj = mysql_query($qrydj);
while($resultsetdj = mysql_fetch_array($resultdj)){
?>
<option value="<?php echo $resultsetdj['user_id']; ?>"><?php echo $resultsetdj['first_name']." ".$resultsetdj['last_name']; ?></option>
<?php
}
?>
</select></td>
</tr>
</table>
<button class="submit" name="submit_feedback" value="submit_feedback">Get Paid!</button>
</form>

When I view the dropdown source it has a value on the select and then on my second page all I have is a simple echo statement to view what was passed like this:

<?php
session_start();
$user_id = $_POST['dj_name'];

echo "The user id is: ".$user_id;
?>

However, when I post this the value selected in the dropdown menu doesn't get passed. In other browsers this works perfectly fine however.

Does anyone have any idea why this isn't working properly?

Thanks!

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1条回答 默认 最新

  • doujingya1166 2012-07-16 23:40
    关注

    You may need to make IE know the button element is in fact submitting the form - Perhaps edit your button:

    <button type="submit" class="submit" name="submit_feedback" value="submit_feedback">Get Paid!</button>
    

    Note that the type attribute is a valid one: http://www.w3schools.com/tags/tag_button.asp

    and html5: http://www.w3schools.com/html5/tag_button.asp

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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