java异常捕获机制:在catch中继续抛出异常，上层调用方不会捕获异常吗？

Question

package Exception;
 
public class exception4 {
    public exception4() {
    }
 
    boolean testEx() throws Exception {
        boolean ret = true;
        try {
            ret = testEx1();
        } catch (Exception e) {
            System.out.println("testEx, catch exception");
            ret = false;
            throw e;
        } finally {
            System.out.println("testEx, finally; return value=" + ret);
            return ret;
        }
    }
 
    boolean testEx1() throws Exception {
        boolean ret = true;
        try {
            ret = testEx2();
            if (!ret) {
                return false;
            }
            System.out.println("testEx1, at the end of try");
            return ret;
        } catch (Exception e) {
            System.out.println("testEx1, catch exception");
            ret = false;
            throw e;
        } finally {
            System.out.println("testEx1, finally; return value=" + ret);
            return ret;
        }
    }
 
    boolean testEx2() throws Exception {
        boolean ret = true;
        try {
            int b = 12;
            int c;
            for (int i = 2; i >= -2; i--) {
                c = b / i;
                System.out.println("i=" + i);
            }
            return true;
        } catch (Exception e) {
            System.out.println("testEx2, catch exception");
            ret = false;
            throw e;
        } finally {
            System.out.println("testEx2, finally; return value=" + ret);
            return ret;
        }
    }
 
    public static void main(String[] args) {
        exception4 testException1 = new exception4();
        try {
            testException1.testEx();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

这是我在学习异常这部分知识时 看到一位博主的文章中举出的例子 这段代码的输出结果是

i=2  
i=1  
testEx2, catch exception  
testEx2, finally; return value=false  
testEx1, finally; return value=false  
testEx, finally; return value=false

我的问题是testEx2方法的catch块中通过throw e;抛出了异常，为什么在testEx1方法中这个异常没有被textEx1方法中的catch块捕获并输出相应语句，这个异常去哪里了呢？帮忙解答一下疑问，感激不尽！

Answer 1

因为testEx1中的这句ret = testEx2();代码有返回值，且返回值为false，所以不再往下执行