doujiyuan0211 2017-06-02 09:08
浏览 66
已采纳

函数定义不使用php接收数组值

I have one function call remove_certificate_packages($certificate_id, array_keys($package_id)) this will invoke the below function

function remove_certificate_packages($certificate_id, $package_id)
{    
    if (is_numeric($package_id)) // so this is list of package id:s
        $package_id = array($package_id);

    if (!$package_id) return true;

    **notify_package_unlinked($certificate_id,array_keys($package_id));**//one more func call

    return true;
}

in this function, I have one more function call "notify_package_unlinked" I need to pass the "$package_id". It will call the appropriate function but the problem is, in the "notify_package_unlinked" function the value is showing "Array". What is the problem? Could you please help

function notify_package_unlinked($certificate_id,$package_id) 
{
      $query="select id,filename,version from packages where id =$package_id";
      $res = db_query($query);
      $package= db_fetch_object($res);

      $packid=$package->id;
      $packname=$package->filename;
      $packversion=$package->version;
      print "$packid"; // here it is printing the value"Array"
 }
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1条回答 默认 最新

  • duanpacan2583 2017-06-05 09:28
    关注

    I got my output using foreach loop .

    foreach($package_id as $id){$pack=$id;}
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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