dongwei1855 2017-01-29 04:02
浏览 65
已采纳

jQuery自动完成功能根据我的输入词从数据库中提取项目,但结果显示为列表的水平线

The jQuery autocomplete function brings the item from the database based on my typing word but result shows as just horizontal line of list. Attached image is showing how the result looks like.

Result

HTML:

<form class="navbar-seach pull-center">
    <div>
        <input type="text" placeholder="Search Productstyle="width:550px; height:40px;padding-left: 10px;margin-top: 20px;" id="searchBox" onkeyup="if (event.keyCode === 13) {searchResults(this.value); this.value = '';}">
    </div>
</form>

PHP:

include 'searchbox.php';

$switch_id = filter_input(INPUT_POST, 'switch_id', FILTER_SANITIZE_SPECIAL_CHARS);

if (isset($_POST['name_startsWith']))
    $searchWordResults = $_POST['name_startsWith'];
else
    $searchWordResults = null;

switch($switch_id){
    case 1:
        $userObj = new searchBox();
        echo $userObj->autoComplete($searchWordResults);
        break;
}

jQuery:

$("#searchBox").autocomplete({
    source: function(request, response) {
        $.ajax({
            type: "POST",  
            url: "class/searchbox_switch.php",
            dataType: "json",
            data: { name_startsWith: request.term, switch_id: 1 },
            success: function(data) {
                response($.map(data, function(item){
                    return {
                        label: item.label,
                        value: item.value
                    };
                }));
            },
            error: function(response) {
                console.log(response.responseText);
            }
        });
    },
    autoFocus: true,
    minLength: 1,
    select: function( event, ui ) {
        searchResults(ui.item.label);
    }
});

PHP (searchbox.php):

include '../dbConnect.php';

class searchBox {
    public function autoComplete($name_startsWith) {
        $letterSearch = $name_startsWith . "%";
        $connectObj = new db_connect();
        $dbh = $connectObj->connect();

        $stmt = $dbh->prepare("SELECT product_name FROM products WHERE product_name LIKE :start");
        $stnd = array();
        $stmt->bindParam(':start', $letterSearch, PDO::PARAM_STR);
        $stmt->execute();
        $stnd = $stmt->fetchAll(PDO::FETCH_ASSOC);
        $json = json_encode($stnd);
        return $json;
    }

}
  • 写回答

1条回答 默认 最新

  • dtrvzd1171 2017-01-31 06:58
    关注

    OK got it. You are passing wrong key in your result. Your result data key is "product_name" And You are trying to access "label ". Try This solution:

     success: function( data ) {                
              response( $.map( data, function(item) {                    
                 return {
                       label: item.product_name,
                 }
              }));                    
    
     },
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 关于#matlab#的问题:在模糊控制器中选出线路信息,在simulink中根据线路信息生成速度时间目标曲线(初速度为20m/s,15秒后减为0的速度时间图像)我想问线路信息是什么
  • ¥15 banner广告展示设置多少时间不怎么会消耗用户价值
  • ¥16 mybatis的代理对象无法通过@Autowired装填
  • ¥15 可见光定位matlab仿真
  • ¥15 arduino 四自由度机械臂
  • ¥15 wordpress 产品图片 GIF 没法显示
  • ¥15 求三国群英传pl国战时间的修改方法
  • ¥15 matlab代码代写,需写出详细代码,代价私
  • ¥15 ROS系统搭建请教(跨境电商用途)
  • ¥15 AIC3204的示例代码有吗,想用AIC3204测量血氧,找不到相关的代码。