duangai1916 2013-08-09 21:45
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查询中变量列名的php语法

I am trying to pass the name of a column as a variable to a PHP database query.

the hard coded syntax works perfectly and is: select max([257612cr]) as price from Price_TekwaniPrice where customeraccount='DAY001'

When I pass the variable I get error trying to get property ofnon object. my syntax is:

        $query = $this->db->query("
select max(['$product']) as price from Price where customeraccount='$customer'
      ");

I also tried:

        $query = $this->db->query("
select max(".$product.") as price from Price where customeraccount='$customer'
      ");

I have confirmed that the variables are being passed correctly. the syntax for '$customer' works perfectly so just passing the $product variable as a column name is proving cumbersome.

I am using php with codeigniter. any advice welcome.

Thanks as always,

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  • douhuan9289 2013-08-09 21:53
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    No need to concatenate a php variable when already opened double quotes try this

     $query = $this->db->query("
    select max([$product]) as price from Price where customeraccount='$customer'
          ");
    

    or

    $query = $this->db->query("
    select max($product) as price from Price where customeraccount='$customer'
          ");
    

    While about the error you are getting is due i think your database driver is not loaded first try to load database

    $this->load->database('default', TRUE);

    The best way to use CI's Active record you can do so

    $this->db->select_max($product);
    $this->db->where('customeraccount', $customer); 
    $query = $this->db->get('Price');
    

    See Active Record

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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