dongxing8009 2011-04-30 19:48
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从mySQL数据库中检索列并传递给数组

I have previously constructed an array manually, e.g.:

<?php
$noupload = array('nick', 'cliff');
?>

but now I am trying to populate the array automatically from users in a MySQL database. So far I have this:

<?php
// Make a MySQL Connection
$debug=false;
$conn = mysql_connect("host","user","password"); // your MySQL connection data
$db = mysql_select_db("database");

$query = "SELECT * FROM users WHERE access LIKE '%listen%'"; 

$result = mysql_query($query) or die(mysql_error());

while($row = mysql_fetch_array($result)){
    $listen = "'". $row['login']. "', ";
}
?>

$listen constructs the user list in the way that I previously entered it manually (I tested this using echo), but I am not sure how to pass this to $noupload. I tried:

$noupload = array($listen);

but this didn't work. I think I'm close and would be grateful for some help over the final hurdle,

Thanks,

Nick

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1条回答 默认 最新

  • dongping1689 2011-04-30 19:51
    关注

    You can declare $listen as an array

    $listen = array();
    while ($row = mysql_fetch_array($result)) {
        $listen[] = "'". $row['login']. "'";
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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