如何在两个下拉菜单中根据列名显示列值

Question

I have a drop down menu; having column names from database table. Now, I have another dropdown menu.

What I want is; When I select column name from first dropdown menu, It shows the values of that selected column name from database table in second dropdown menu.

I have inserted column names for the first dropdown menu in options tag but i want to retrieve all column values based on selected column name from database table.

Here is my code:

<select name="first">

  <option selected="true" disabled="disabled">Select an Option</option> 
  <option value="all">Select All</option>   
  <option value="a">a</option>
  <option value="b">b</option>
  <option value="c">c</option>
  <option value="d">d</option>
</select>

Where a,b,c,d are the column names. Please help me out.

Answer 1

You can try like this

HTML:

    <select name="category">
    <option value="0">None</option>
    <option value="1" rel="accessories">Novels</option>
    <option value="2" rel="sports">Scooties</option>
    <option value="3" rel="cars">Bikes</option>
</select>


<select name="items" class="cascade">
    <option value="3" class="accessories">Immortals of meluha/option>
    <option value="8" class="accessories">Half Girlfriend</option>
    <option value="1" class="sports">Active 5G</option>
    <option value="4" class="sports">Active 4G</option>
    <option value="6" class="cars">Royal Enfield</option>
    <option value="2" class="cars">Pulsor</option>
</select>

JQUERY :

$(document).ready(function(){
    var $cat = $('select[name=category]'),
        $items = $('select[name=items]');

    $cat.change(function(){
        var $this = $(this).find(':selected'),
            rel = $this.attr('rel'),
            $set = $items.find('option.' + rel);

        if ($set.size() < 0) {
            $items.hide();
            return;
        }

        $items.show().find('option').hide();

        $set.show().first().prop('selected', true);
    });
  });