douguan8940 2015-08-17 15:23
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试图用POST方法替换GET方法

<form action="process.php" method="post">
    <input type="submit" name="p" value="<?php echo $row['tID'];?>"/>
</form>

I have the above button to send it's value to another page to renew the query results on it's own page with it's own value.

the query looks like this:

    $p = $_POST['p'];
    $safe_p =  mysqli_real_escape_string($dcon, $p);
    $sql1 = 'SELECT * FROM bla bla... WHERE tID = '.$safe_p.' ';

I was using $_GET and a href link before and it was working; but everybody says I should use more secure ways. So now I want to switch to POST.

Button shows it's value alright and all I did on the query page was changing the GET to POST so What's wrong with this query?

edit: I worked it out. The problem was not the query or the button. I just needed to set form action to the correct page. So it was me. instead of the query itself, I directed the form to the result page and it's working now.

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  • doumu4916 2015-08-22 17:17
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    I worked it out. The problem was not the query or the button. I set form action to the correct page.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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