dtgvl48608 2015-09-17 02:08
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如何知道图像的地理位置(十进制格式)

Any easiest way to get the latitude and longitude of an image, in decimal degree format?

$exif = exif_read_data($photos['file_path'],0, true, false);
                        print_r($exif); 

what i got in this:

   [GPS] => Array
        (
            [GPSLatitudeRef] => N
            [GPSLatitude] => Array
                (
                    [0] => 13/1
                    [1] => 57/1
                    [2] => 1032/100
                )

            [GPSLongitudeRef] => E
            [GPSLongitude] => Array
                (
                    [0] => 121/1
                    [1] => 9/1
                    [2] => 5137/100
                )

            [GPSAltitudeRef] => 
            [GPSAltitude] => 344/1
            [GPSTimeStamp] => Array
                (
                    [0] => 10/1
                    [1] => 12/1
                    [2] => 5292/100
                )

            [GPSSpeedRef] => K
            [GPSSpeed] => 0/1
            [GPSImgDirectionRef] => T
            [GPSImgDirection] => 32993/102
            [GPSDestBearingRef] => T
            [GPSDestBearing] => 75030/523
            [GPSDateStamp] => 2015:07:28
        )

Anyone here can help me to convert this things in decimal degree format?

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1条回答 默认 最新

  • douxia5179 2015-09-17 08:08
    关注

    It looks like GPSLatitude[0] is Degrees, GPSLatitude[1] is Minutes, and GPSLatitude[2] is Seconds and so on but coded as 'whole number' / 'denominator'

    Here is some code that does the calculation:

    $exif = exif_read_data("your-image-file-with-GPS-exif-data.JPG",0, true, false);
    if (isset($exif['GPS'])) {
        $longitude_array = $exif['GPS']['GPSLongitude'];
        $latitude_array = $exif['GPS']['GPSLatitude'];
    } else {
        die("no exif GPS");
    }
    
    function GPScalc($string) { // function to calculate the EXIF encoded string
        $GPSparts = explode("/",$string);
        return $GPSparts[0] / $GPSparts[1];
    }
    
    function GPSdec($GPSarray) { // function to put the exif parts together to decimal degrees
        return GPScalc($GPSarray[0]) + 
               GPScalc($GPSarray[1])/60 + 
               GPScalc($GPSarray[2])/3600;
    }
    
    $longitude_decimal_degree=GPSdec($longitude_array);
    $latitude_decimal_degree=GPSdec($latitude_array);
    
    print "Longitude = $longitude_decimal_degree , Latitude = $latitude_decimal_degree";
    

    This will output something like:

    Longitude = 1.632425 , Latitude = 53.297658333333

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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