dongling4288 2014-05-29 16:21
浏览 121

将变量传递给视图CodeIgniter时失败

I trying to pass $variable from CodeIgniter controller to a view but it's fail.

My controller code is:

class Index_controller extends CI_Controller {
    public function index(){
        $formURL = base_url().index_page().'authorization_controller/authorization';
        $attributes = array('class' => 'authorization','id' => 'authorization');
        $this->load->view('header');
        $this->load->view('leftFrame', $formURL, $attributes);
        $this->load->view('rightFrame');
        $this->load->view('index');
        $this->load->view('footer');
    }
}

My view code is:

<?php echo form_open($formURL, $attributes); ?>
</form>

Error message:

A PHP Error was encountered
Severity: Notice
Message: Undefined variable: formURL

and

A PHP Error was encountered
Severity: Notice
Message: Undefined variable: attributes
  • 写回答

2条回答 默认 最新

  • drudfe0446838 2014-05-29 16:24
    关注

    You need to pass the data in an array or an object. You can then access this data by referencing a variable of the same name as the array key in the view. You can achieve this like this:

    public function index()
    {
        $formURL = base_url().index_page().'authorization_controller/authorization';
        $attributes = array('class' => 'authorization','id' => 'authorization');
    
        // Data to pass to the view
        $view_data['formURL'] = $formURL;
        $view_data['attributes'] = $attributes;
    
        $this->load->view('header');
        $this->load->view('leftFrame', $view_data);
        $this->load->view('rightFrame');
        $this->load->view('index');
        $this->load->view('footer');
    }
    
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