dongzhan9100
2012-05-06 08:39
浏览 766
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发生错误:SyntaxError:JSON.parse:意外字符

I'm trying to update a record with JQuery/JSON but I'm seeing this error:

An error has occurred:

[object Object]

parsererror

SyntaxError: JSON.parse: unexpected character

My JS:

jQuery('#commentForm').live('submit', function (event) {
event.preventDefault()


jQuery.ajax(edit_url, {
    data: jQuery(this).serialize(),
    dataType: 'json',
    type: 'POST',
    success: function (data) {
        if (data.error === 'OK') {
            alert('ok c good')
        } else {
            alert('hi' + data.error)
        }
    },
    error: function(x,y,z){
        alert('An error has occurred:
' + x + '
' + y + '
' + z);
    }
})

return false;
})

And my php:

$ret = array(
    'error'             =>  'OK',
);
$update =
    "UPDATE crm_set_users SET ".
        "crm_set_users_civilite = '".mysql_real_escape_string($crm_set_users_civilite)."',".
        "crm_set_users_nom = '".mysql_real_escape_string($crm_set_users_nom)."',".
        "crm_set_users_prenom = '".mysql_real_escape_string($crm_set_users_prenom)."',".
        "crm_set_users_email = '".mysql_real_escape_string($crm_set_users_email)."', ".
        "crm_set_users_telephone = '".mysql_real_escape_string($crm_set_users_telephone)."', ".
        "crm_set_users_portable = '".mysql_real_escape_string($crm_set_users_portable)."'";

if($crm_set_users_photo != ""){
    $update .=", crm_set_users_photo = '".mysql_real_escape_string($crm_set_users_photo)."'";
}   

$update .=
    "WHERE ".
        "crm_set_users_id = '".mysql_real_escape_string($user_id)."'";




echo json_encode($ret);
exit;

If my php is :

$ret = array(
    'error'             =>  'OK',
);
echo json_encode($ret);
exit;

then it works...

Tks for you help!

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2条回答 默认 最新

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