douchengfei3985 2015-05-05 18:14
浏览 98
已采纳

Laravel过滤器传递并转到请求的URL

I am trying to setup laravel filter in my app.

here is my code,

Filter.php

Route::filter('userid', function($route,$request,$value)
{
 $id = Auth::user()->id;
 $param = $route->getParameter('id');

    $count = DB::table('timesheets')
    ->where('timesheet_id','=',$param)
    ->where('timesheet_user','=',$id)
    ->count();

   if($count == 1)
   {
    return "here going to requested url";
   }
   else
   {
    return "no permission to this page";
   }

});

My Routes,

Route::group(array('before'=>'userid:200'),function($route)
 {
    Route::get('edit-timesheet-{id}',array('as'=>'edit_timesheet_form','uses'=>'TimesheetController@editEntry'));
});

I am getting the parameters and checking with filter.php was fine.

But when a user click on the edit-timesheet-756, if the filter is success, then it needs to continue the execution of the URL, How can i solve this.

Thanks & Regards

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3条回答 默认 最新

  • douou9786 2015-05-07 15:51
    关注

    Finally I got the solution.

    just give blank in true condition.

     if($count == 1)
     {
       // here left as blank
     }
     else
     {
      return "no permission to this page";
     }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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