如何使用PHP检查日期是否为今天的日期

Question

Say, I have 4 dates and the date today is 1/7/16:

1/7/16 1:06:02

1/7/16 8:01:24

1/8/16 7:02:23

1/6/16 3:12:34

How can I only pick 1/7/16 1:06:02 and 1/7/16 8:01:24.

What date function from PHP can I use to only get the date of today?

Thanks!

UPDATE:

This is being used as a MYSQL selector.

Example: $db->query("DELETE * FROM entry WHERE date='$today'");

How would this work? How can I get my MYSQL query to select only the dates for today?

UPDATE 2: I've tried using curdate(), but the code is not working... This is what I'm doing:

$db->query("DELETE * FROM entry WHERE date=curdate()"); 

What am I doing wrong?

LAST UPDATE: curdate() worked properly...

Answer 1

UPDATE: As MySQL query, you can do this as follows:

$db->query("DELETE * FROM entry WHERE DATE(date) = CURDATE()");

CURDATE() returns today's date.

If you want to do with php, see below to use the DateTime class.

$now = new DateTime;
$otherDate = new DateTime('2016-01-01'); // or e.g. 2016-01-01 21:00:02

var_dump($now->diff($otherDate)->days === 0); // Today
var_dump($now->diff($otherDate)->days === -1); // Yesterday
var_dump($now->diff($otherDate)->days === 1); // Tomorrow