函数返回NULL而不是值[duplicate]

Question

This question already has an answer here:

• Reference: What is variable scope, which variables are accessible from where and what are “undefined variable” errors? 3 answers

I wrote a function that I thought cannot be more basic:

In functions.php:

function testowa() {
$stringToReturn = "pies";
return $stringToReturn;
}

Then I'm trying to call it in single.php:

include_once ('functions.php');

testowa();
var_dump($stringToReturn);

And var_dump displays NULL.

Where could I possibly do anything wrong?

</div>

Answer 1

You have to assign the function's response to a variable. Try

$stringToReturn = testowa();
var_dump($stringToReturn);