PHP数组如何判断字符是否未找到？

Question

i have an example code like this :

$a = "A";
$b = array("A", "B", "C");

foreach ($b as $value) 
{
    $checkName = strpos($a, $value);

    if($checkName !== false)
    {
        echo "K";
    }
    else 
    {
       echo "b";
    }
}

if i run above code, will show "KBB".

how when we already found the string we only echoing "K" ? so what i want is,

1. Find a string in array,
2. if found echo k,
3. if not found echo b.

Answer 1

It is a question of simple linear search:

$a = "A";
$b = array("A", "B", "C");

$found = FALSE;

foreach ($b as $value) 
{
    if($value == $a)
    {
        $found = TRUE;
        break;
    }
}

if($found)
    echo 'k';
else
    echo 'b';

Hope, it helps.

Thanks and Regards.