dqfsbvd43312 2015-08-11 08:00 采纳率: 0%
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通过Ajax请求打印数据输出请求不起作用

I have made a form, which on submit goes to a php file (save.php) and echoes the name back, which after taken as response is alerted in the index.html. Somehow I cannot print back the name which was send to php. Pls help.

HTML

<html>
<head>
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
    <script>
        $(document).ready(function(){
            $('#submit1').click(function(){
                $.ajax({
                    type: "POST",
                    url: "save.php",
                    data: jQuery("#form1").serialize(),
                    cache: false,
                    success:  function(data){
                       /* alert(data); if json obj. alert(JSON.stringify(data));*/
                       alert(data);
                    }
                });
            });
        });
    </script>
</head>

<div class="form_wrapper">
    <form id="form1">
        Name:<input id="name1" type="text" /> <br/>
        Email:<input id="email1" type="email" /><br/>
        <input id="submit1" type="submit" />
    </form>
</div>
</body> 
</html>

PHP:

<?php

$name = $_POST['name1'];
$email = $_POST['email1'];
echo $name;

?>

Kindly, help!

ERROR:

Notice: Undefined index: name1 in C:\xampp\htdocs\example3\save.php on line 3

Notice: Undefined index: email1 in C:\xampp\htdocs\example3\save.php on line 4
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3条回答 默认 最新

  • dongyong8071 2015-08-11 08:09
    关注

    Give your input feild a name and access $_POST['given_name'] in php

    Thank you :)

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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