在PHP中将未知数转换为数组

Question

I have a query that returns either an object or an array based on the number of items. If there are zero or one items being returned, then it returns the item as an object. If there are two or more items, then it returns an array of objects.

I'm wanting to do a foreach on the query result, but that is throwing an error if it is an object that is returned, rather than an array. So I've created a function that would convert an object to an array.

function to_array($unknown) {
  if (count($unknown) === 0) {
    $array=array($unknown);
  } elseif (!is_array($unknown)) {
    $array = array();
    $array[0] = $unknown;
  } else {
    $array = $unknown;
  }
  return $array;
}

It can be used by simply calling $query_array = to_array($query_return).

Is this be best way to do this? Is there a better way? Might this create any problems?

Answer 1

I'm wanting to do a foreach on the query result, but that is throwing an error if it is an object that is returned, rather than an array.

It seems your data source is somewhat unclear or unclean. We are talking about queries, objects and arrays. Who knows what else is possible, the more your data source evolves. Therefore, I would check the data type first and handle all possibilities.

The gettype function gives you a good starting point. Then you can use a switch to handle all possibilities, even future PHP Modifications as below.

For the object to array conversion, I would use the get_object_vars function instead of a simple type cast, because it is unclear to me what that type cast really would do. But the get_object_vars function is well documented.

$type = gettype ( $unknown );
switch ($type) {
  case "array":
    $array = $unknown;
    break;
  case "object":
    $array = get_object_vars ( $unknown );
    break;
  case "boolean":
  case "integer":
  case "double": 
  case "string":
  case "resource":
  case "NULL":
  case "unknown type":
  default: throw new Exception("Unknown data type");
}

/* Do something here with $array */