Ajax图像上传通知

Question

i think i sleep already, cant find my mistake. Thanks for your advance for this short post and for your help.

My Javascript

$("#avatarImage").change(function() {
    $("#avatar").html('<img src="assets/images/loader.gif" alt="">');
    $.post( 'ajax/avatarUpload.php', function( data ) {
        alert(data);
    });
});

My Form

<form enctype="multipart/form-data" method="post" action="ajax/avatarUpload.php" id="avatarUpload">
    <span class="btn btn-teal btn-file btn-sm"><span class="fileupload-new"><i class="fa fa-pencil"></i></span><span class="fileupload-exists"><i class="fa fa-pencil"></i></span>
        <input type="file" name="avatar" id="avatarImage">
    </span>
</form>

My PHP Code

$file_up_size = $_FILES['avatar']['size'];
$file_name = md5(uniqid(rand(), true));
$add = '../assets/images/avatars/' . $file_name;

if(!move_uploaded_file($_FILES['avatar']['tmp_name'], $add)){
    echo 'FEHLER';  
} else {
    //database crap
}

My Error(s)

Notice:  Undefined index: avatar in ...

Thanks for your help, i am blind this evening.

Answer 1

Your $.post() is posting to the form but it is not supplying any data to that form. This is causing undefined index: avatar because your post doesn't include an index of avatar within the files array. To resolve this, pass along the image in your POST by constructing a FormData object. Further, the ajax wrapper $.post() doesn't allow you to set certain options, and therefore we need to unwrap it and use $.ajax() instead.

$("#avatarImage").change(function() {
    $("#avatar").html('<img src="assets/images/loader.gif" alt="">');
    var fd = new FormData()
    fd.append('avatar', $('#avatarImage')[0].files[0]);

    $.ajax({
        url: 'ajax/avatarUpload.php',
        type: 'POST',
        data: fd,
        contentType: false,
        processData: false,
        success: function(data){
            console.log(data);
        }
    });
});