php正则表达式检测所有内容甚至换行

Question

this is my input :

<div class="entry-content">
    <p> Hey ! </p>
    <h2> How Are You ?! </h2>
</div><!-- .entry-content -->

and this is my RegEx !

"<div class=\"entry-content\">(.*?)</div><!-- .entry-content -->"

this work when there is no line between <div> tag like this

<div class="entry-content"> Hey ! </div><!-- .entry-content -->

But i need actually everything even new line other html tags and etc.

Answer 1

You should use XML Parsing framework like DOM to parse XML documents (including HTML), but if you really need to use regex (assuming PCRE) there's an s PCRE modifier:

s (PCRE_DOTALL)

If this modifier is set, a dot metacharacter in the pattern matches all characters, including newlines. Without it, newlines are excluded. This modifier is equivalent to Perl's /s modifier. A negative class such as [^a] always matches a newline character, independent of the setting of this modifier.

So you may write:

$matches = array();
preg_match_all("~<div class=\"entry-content\">(.*?)</div><!-- \\.entry-content -->~s",
    $text, $matches);

BTW: Here's an example for you how to use DOM to fetch elements based on their class name.