计算2x成人+ 2x儿童组合的数量

Question

• a ticketing site offers a discount on "family" tickets.
• a family ticket is 2 adults, 2 children.
• the sell tickets page allows a user to enter any number of adult and child tickets.

How do I work out how to apply the family ticket discount, then charge all remaining tickets at their relevant cost (i.e. adult tickets cost more than child tickets) ?

Here's what I have so far (seems to work, but not 100% confident about it (php))

# Work out how many pairs of people there are
$numAdultPairs = floor($oForm->adult / 2);
$numChildPairs = floor($oForm->child / 2);

# work out the number of matching pairs for child / adult
if ( $numAdultPairs > $numChildPairs ) {
    $numberOfFamilyTickets = $numAdultPairs - $numChildPairs;
} else if ( $numAdultPairs < $numChildPairs ){
    $numberOfFamilyTickets = $numChildPairs - $numAdultPairs;
} else if ( $numAdultPairs == $numChildPairs ) {
    $numberOfFamilyTickets = $numAdultPairs;
}

# work out the remaining tickets required
$remainingAdult = $oForm->adult % 2;
$remainingChild = $oForm->child % 2;

Answer 1

I don't think your approach actually works. Assume you have 6 adults and 4 children. In this case your first if would be true and you would end up with 3 - 2 = 1 family ticket. The correct result would be two family tickets and two adult tickets, though.

You want the lowest number of pairs to determine the amount of family tickets. Try something like this:

$numberOfFamilyTickets = min($numAdultPairs, $numChildPairs);
$remainingAdult = $oForm->adult - 2 * $numberOfFamilyTickets;
$remainingChild = $oForm->child - 2 * $numberOfFamilyTickets;

Assuming you make sure that $oForm->adult and $oForm->child are non-negative.