dongweishi2028 2012-09-12 17:28
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如何在PHPUnit中验证此函数是否为字符串?

Here's the code for my original PHP code:

public function outputText() {   
    $i = 1;   
    foreach($this->sorted_data as $this->data) {   
        echo "$i. ".$this->data[0]."<br/>";   
        $i++;  
    }  
}

And here's the code for the PHPUnit:

public function testVerify() {
    $yn = new SortThisData();
    $yn->readFile("input.txt");
    $output = $yn->outputText();
    $this->assertTrue(is_string($output));

    //if(!is_string($yn->get()))
    //    return false;
    //$this->assertNotEmpty($yn->get());
    }

The class is called SortThisData in the original PHP file. When I used gettype(), it said it was null. I'm trying to verify that it is a string so it can pass in PHPUnit. Is there a way I can do this?

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2条回答 默认 最新

  • dqrm8199 2012-09-12 17:32
    关注

    You're looking for assertInternalType().

    Update: I didn't realize you were echoing the output. You will probably need to use output buffering to capture the text.

    public function testVerify() {
        $yn = new SortThisData();
        $yn->readFile("input.txt");
    
        // start output buffering and capture the output
        ob_start();
        $yn->outputText();
        $output = ob_get_clean();
    
        $this->assertInternalType('string', $output);
    }
    
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