douwa0280 2011-11-07 19:52
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php strtotime和锻炼多年?

I have a date stored in my mysql database and I can workout the days since the date like so,

 ceil(time() - strtotime($account['joined']) / 60 / 60 / 24 % 365);

But how can I work out the years, since years is the highest format of time, since after that it is millenia and such?

The variable is one such as:

2011-10-06 22:01:57

Thanks

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  • dougan4663 2011-11-07 19:57
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    Use date("Y")

    <?php 
    $time = strtotime("1 Jan 2001 1:11:11"); 
    echo "Years since time: ".(date("Y") - date("Y", $time));
    

    http://sandbox.phpcode.eu/g/220fe/1

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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