使用内部联接查询显示2个表

Question

Hey guys i want to show a table so that table have 2 foreign keys.My food and restaurant table have name column.i tried following codes but i dont know how to show restaurant name and food name different.

$sql_select_food = "SELECT food.id,restaurant.name,food.name,food.restaurant_id,foodcategory.title from food INNER join foodcategory ON food.foodcategory_id=foodcategory.id INNER join restaurant ON food.restaurant_id=restaurant.id WHERE food.isActive = 1 ORDER BY food.updateDate DESC";
$result_select_food = mysqli_query($connection, $sql_select_food);
if (mysqli_num_rows($result_select_food) > 0) {
      while ($row_select_food = mysqli_fetch_assoc($result_select_food)) {
                        echo "
                            <tr>
                                <td>$row_select_food[name]</td>
                                <td>$row_select_food[name]</td>
                                <td>$row_select_food[title]</td>
                            </tr>
                ";
                    }
                }

Answer 1

Use column aliases:

SELECT food.id AS food_id, restaurant.name AS restaurant_name, food.name AS food_name ...

Then

• $row_select_food['restaurant_name'] is the name of the restaurant,
• $row_select_food['food_name'] is the name of the food,
• etc.

Note: AS keyword is optional.