请问这段代码最终得出的getKey()的值是什么

Question

package com.ahtv.application;

import android.util.Base64;
import java.io.PrintStream;
import javax.crypto.Cipher;
import javax.crypto.spec.SecretKeySpec;

public class CryptAES
{
public static String jmkey = "VatC3b0zAqpLmAkE";

public static String decrypt(String paramString1, String paramString2)
{
try
{
SecretKeySpec localSecretKeySpec = new SecretKeySpec(paramString2.getBytes(), "AES");
Cipher localCipher = Cipher.getInstance("AES/ECB/PKCS5Padding");
localCipher.init(2, localSecretKeySpec);
byte[] arrayOfByte2 = localCipher.doFinal(Base64.decode(paramString1, 0));
arrayOfByte1 = arrayOfByte2;
}
catch (Exception localException)
{
for (;;)
{
System.out.println(localException.toString());
byte[] arrayOfByte1 = null;
}
}
return new String(arrayOfByte1);
}

public static String encrypt(String paramString1, String paramString2)
{
try
{
SecretKeySpec localSecretKeySpec = new SecretKeySpec(paramString2.getBytes(), "AES");
Cipher localCipher = Cipher.getInstance("AES/ECB/PKCS5Padding");
localCipher.init(1, localSecretKeySpec);
byte[] arrayOfByte2 = localCipher.doFinal(paramString1.getBytes());
arrayOfByte1 = arrayOfByte2;
}
catch (Exception localException)
{
for (;;)
{
System.out.println(localException.toString());
byte[] arrayOfByte1 = null;
}
}
return new String(Base64.encodeToString(arrayOfByte1, 0));
}

public static String getKey()
{
if ((jmkey != null) || (!"".equals(jmkey)))
{
char[] arrayOfChar1 = jmkey.toCharArray();
char[] arrayOfChar2 = new char[jmkey.length()];
for (int i = 0; i < arrayOfChar1.length; i++) {
arrayOfChar2[i] = arrayOfChar1[(-1 + arrayOfChar1.length - i)];
}
return new String(arrayOfChar2);
}
return "EkAmLpqAz0b3CtaV";
}

public static void main(String[] paramArrayOfString)
{
System.out.println(getKey());
}
}

Answer 1

getKey()里面直接将jmkey逆序输出了一下，并没有调用别的代码