在另一个PHP中执行PHP

Question

I have following 2 php pages which is actually containing html tags (in 2nd page only) with out php tag start and end.

page1.php

<div>Page 1</div>
<?php exec('/usr/bin/php page2.php');
?>

page2.php in same directory

<div> this is page 2</div>

Actual result : 2nd page is not printed when page1.php is executed

Expected result: both page 1 and page 2 php result should come in page1.php when hit from broswer.. in this case , following is the expected result..

Page 1
this is page 2

Note : This is just an example. my page is containing 1000s of lines in page2.php

Answer 1

You're looking for require or include (or in particular, probably require_once)

i.e.

<div>Page 1</div>
<?php 
    require("page2.php");
?>

Unless you're trying to do something far stranger than i've anticipated.