dongpan8928 2014-12-01 17:03
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日期检查通过的时间量

I am trying to check if the user has been on the site longer then 6 months, if they have to prompt a message.

I cannot get this to work, it keeps thinking 6 weeks has passed even when the date is moved to today.

Currently my code.

            $created_at = "2014-12-01 16:58:23";

            $sixweek = 604800 * 6;

            if(strtotime($created_at) < time() + ($sixweek))
            {
                $data['needsnewimage'] = 1;
                die('6 Weeks has passed ');

            }else{
                $data['needsnewimage'] = 0;
                die('6 Weeks has not passed');
            }

Any ideas?

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2条回答 默认 最新

  • duanbiao4025 2014-12-01 17:07
    关注

    That's not going to work. Consider this: someone signs up for your site TODAY:

    $created_at = '2014-12-01 08:00:00'; // "today"
    
    if ($created_at < $today + $sixweek) ...
    

    becomes

    if ($today < $today + $sixweek)
    if (0 < $sixweek)
    

    and will always be true.

    You want

    if ($created_at > (time() - $sixweek))
                    ^---------^
    

    Note the changed math

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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