douwen4178 2013-10-31 09:53
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使用ajax读取php文件呈现的html

I am just trying to read the file content of a rendering HTML of URL

Here the code i am using , its always going in error section .

  $.ajax({
            type: 'POST',
            url: 'http://www.withholding32.com/api/wh32calc.php?userid=nick&fpp=12&ffs=Single&fa=0&fgp=6000&figp=0&fiytd=0&st=6&stp=6000&ss=Single&sa=0&sad=0&stca=0',
            dataType: 'html',
            success: function(data) {
                alert('success');
            },
            error: function(XMLHttpRequest, textStatus, errorThrown) {
                alert('error');
            }
        });

but in case i run the same url directly in browser , its show me html.

here is url

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4条回答 默认 最新

  • duanpin5168 2013-10-31 11:44
    关注

    Try the below code:

       $('document').ready(function() {
    
          $.getJSON('http://anyorigin.com/get?url=' + 
          encodeURIComponent('http://www.withholding32.com/api/wh32calc.php?userid=nick&fpp=12&ffs=Single&fa=0&fgp=6000&figp=0&fiytd=0&st=6&stp=6000&ss=Single&sa=0&sad=0&stca=0') + '&callback=?',
    
          function(data){
             $("#result").html(data.contents);
    
           });
    
    });
    

    Refer : http://jsfiddle.net/R7EPt/275/

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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