dongpu7881
2014-07-20 20:58
浏览 137
已采纳

如何在强制浏览器下载PHP时显示文件大小

I'm downloading mp4,mp3 etc.. files from my server with php. But browsers are not showing the size of file. I searched everywhere but i couldn't find any working answer. Hope you can help me. Thanks in advance.

Here is the code :

  function force_download($file)
 {
 $ext = explode(".", $file);
 switch($ext[sizeof($ext)-1])
{
  case 'jar': $mime = "application/java-archive"; break;
  case 'zip': $mime = "application/zip"; break;
  case 'jpeg': $mime = "image/jpeg"; break;
  case 'jpg': $mime = "image/jpg"; break;
  case 'jad': $mime = "text/vnd.sun.j2me.app-descriptor"; break;
  case "gif": $mime = "image/gif"; break;
  case "png": $mime = "image/png"; break;
  case "pdf": $mime = "application/pdf"; break;
  case "txt": $mime = "text/plain"; break;
  case "doc": $mime = "application/msword"; break;
  case "ppt": $mime = "application/vnd.ms-powerpoint"; break;
  case "wbmp": $mime = "image/vnd.wap.wbmp"; break;
  case "wmlc": $mime = "application/vnd.wap.wmlc"; break;
  case "mp4s": $mime = "application/mp4"; break;
  case "ogg": $mime = "application/ogg"; break;
  case "pls": $mime = "application/pls+xml"; break;
  case "asf": $mime = "application/vnd.ms-asf"; break;
  case "swf": $mime = "application/x-shockwave-flash"; break;
  case "mp4": $mime = "video/mp4"; break;
  case "m4a": $mime = "audio/mp4"; break;
  case "m4p": $mime = "audio/mp4"; break;
  case "mp4a": $mime = "audio/mp4"; break;
  case "mp3": $mime = "audio/mpeg"; break;
  case "m3a": $mime = "audio/mpeg"; break;
  case "m2a": $mime = "audio/mpeg"; break;
  case "mp2a": $mime = "audio/mpeg"; break;
  case "mp2": $mime = "audio/mpeg"; break;
  case "mpga": $mime = "audio/mpeg"; break;
  case "wav": $mime = "audio/wav"; break;
  case "m3u": $mime = "audio/x-mpegurl"; break;
  case "bmp": $mime = "image/bmp"; break;
  case "ico": $mime = "image/x-icon"; break;
  case "3gp": $mime = "video/3gpp"; break;
  case "3g2": $mime = "video/3gpp2"; break;
  case "mp4v": $mime = "video/mp4"; break;
  case "mpg4": $mime = "video/mp4"; break;
  case "m2v": $mime = "video/mpeg"; break;
  case "m1v": $mime = "video/mpeg"; break;
  case "mpe": $mime = "video/mpeg"; break;
  case "mpeg": $mime = "video/mpeg"; break;
  case "mpg": $mime = "video/mpeg"; break;
  case "mov": $mime = "video/quicktime"; break;
  case "qt": $mime = "video/quicktime"; break;
  case "avi": $mime = "video/x-msvideo"; break;
  case "midi": $mime = "audio/midi"; break;
  case "mid": $mime = "audio/mid"; break;
  case "amr": $mime = "audio/amr"; break;
  default: $mime = "application/force-download";
 }
header('Content-Description: File Transfer');
header('Content-Type: '.$mime);
header('Content-Disposition: attachment; filename='.basename($file));
header('Content-Transfer-Encoding: binary');
header('Expires: 0');
header('Cache-Control: must-revalidate, post-check=0, pre-check=0');
header('Pragma: public');
header('Content-Length: '. filesize($file));
ob_clean();
flush();

 readfile($file);
}   

if (isset($_POST['downl'])){
$file = "http://localhost/project1/downloads/gmf.mp4";
force_download($file); 

}
<form  method="POST" action=''>
    <?php echo'<input type="submit" name="downl"  value="Download Baby" >' ;    ?>
</form>

If i try to show file size with echo filesize($file) it gives this error :

 Warning: filesize(): stat failed for http://localhost/project1/downloads...
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1条回答 默认 最新

  • duanqi6274 2014-07-20 21:04
    已采纳

    Since php 5.0.0 the file command supports http wrappers but the http wrapper does not support stat commands like size. So you cannot get the file size in your case with size.

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