将帖子参数放入URL

Question

I use CakePHP 2.5.2. I have standard form, which I send by POST method.

I catch this post in controller and display data from database, but when someone refreshes the page, I can't read data again because parameters were provided by a POST request. So, I want to build URL like this:

http://example.com/controller/action/**firstDataFromPost**/**secondDataFromPost**

It makes my site refreshable, but I don't know how modify URL.

Answer 1

There are really two main options here:

Use GET

Using the GET HTTP method instead of POST will mean your variables are automatically appended to the end of the querystring:

http://example.com/controller/action?firstDataFromPost&secondDataFromPost

Redirect after POST

You can post your form to an action that will assemble the variables required and redirect you to a page that doesn't have a dependent HTTP action anymore. Say you post to receive() action:

public function receive() {
    $var1 = $this->data['MyForm']['my_field1'];
    $var2 = $this->data['MyForm']['my_field1'];
    $this->redirect(array('action' => 'showresults', $var1, $var2));
}

Then your showresults() action has passed parameters accessible at all times:

public function showresults($var1, $var2) {
    // ... display your results here using these variables
}

... and your URL would look something like this:

http://example.com/controller/showresults/VAR1HERE/VAR2HERE