duandeng1824 2014-02-01 14:58
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url的语法使用url中的变量

I have the following script in php:

<?php

$my_array_of_vars['v'];

    $row['comment'] = "<img src='http://img.youtube.com/vi/xxxxxx/hqdefault.jpg' title='YouTube Video' alt='YouTube Video' /> ";

?>

All I want is to replace the "xxxxxx" with the result in variable $my_array_of_vars['v']; I have tried a lot of things but always getting wrong result. Any idea how to do this please?

This is what I have tried:

<?php
    $row['comment'] = "<img src='http://img.youtube.com/vi/$my_array_of_vars['v']/hqdefault.jpg' title='YouTube Video' alt='YouTube Video' /> ";
?>
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3条回答 默认 最新

  • duanjiao3686 2014-02-01 15:00
    关注

    You could use those fancy brackets {} like this:

    $row['comment'] = "<img src='http://img.youtube.com/vi/{$my_array_of_vars['v']}/hqdefault.jpg' title='YouTube Video' alt='YouTube Video' /> ";
    

    or properly concatenate the variable to the string:

    $row['comment'] = "<img src='http://img.youtube.com/vi/".$my_array_of_vars['v']."/hqdefault.jpg' title='YouTube Video' alt='YouTube Video' /> ";
    
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