dsn46282 2013-11-12 02:54
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即使它起作用,函数也不会返回true

I have a small piece of code inside a function buts it's not working, even when I pull it out and try it on its own it still doesn't work. I used a MySQL Database Class https://github.com/ajillion/PHP-MySQLi-Database-Class

    require_once('class.mysql.php');
    $_db = new Mysqlidb('localhost', 'root', '', 'database');


    $userCredentials = array(
                        'userID' => 'asdasda',
                        'username' => 'dsdasdasd',
                        'password' => 'v423423c342c23',
                        'email' => '2423v423@gmail.com',
                        'userType' => 1,
                    );

    if($_db->insert('users', $userCredentials)) echo 'success';

The correct data is inserted into the database but Success is not displayed, is their a reason for this?

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  • doupiao9318 2013-11-12 02:59
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    Mysqlidb::insert is wrong. It's return $stmt->insert_id instead of $stmt->execute();. Your query does not use autoincrement value, so, you are getting 0.

    Tip from comments:

    do not use this library

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