du512053619 2013-02-13 12:30
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跨类参数

I have these 2 classes in 2 different files

class Foo {      
  public $type = int;    
  function __construct($out = 1) {        
    $this->type=$out;    
  }

  public function get() {    
    return $this->type;    
  }    
}

AND

class bar {    
  function __construct {    
    echo $foo->get();    
  }    
}

maybe a dumb question but how come this is not working? In the above index.php file I have

 $vFoo = new Foo(15);
 $vBar = new Bar();

I though that Bar will echo Foo's type..

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  • drfu80954 2013-02-13 12:34
    关注

    There is no $foo variable anywhere in your code and if it was, it would be out of scope. A class is not an object, learn the basics.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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