preg_replace：仅在大括号内删除注释

Question

I have this:

$text = 'This is some text /*Comment 1 */ . Some more text{ This is to let you know that /* this is a comment*/. A comment /*this one is */ can be anything }. So the next thing { This is to let you know that /*  this is a comment*/. A comment /*this one is */ can be anything } is another topic. /*Final comment*/';

Need this:

$text = 'This is some text /*Comment 1 */ . Some more text{ This is to let you know that . A comment  can be anything }. So the next thing { This is to let you know that . A comment  can be anything } is another topic. /*Final comment*/';

Tried this:

$text = preg_replace("/\/\*.*?\*\//", "", $text);

The problem is that what I have tried, is removing all the comments. I just want the comments appearing within { } to be removed. How to do this?

Answer 1

This is probably the safest way:

<?php

$text = 'This is some text /*Comment 1 */ . Some more text{ This is to let you know that /* this is a comment*/. A comment /*this one is */ can be anything }. So the next thing { This is to let you know that /*  this is a comment*/. A comment /*this one is */ can be anything } is another topic. /*Final comment*/';

$text = preg_replace_callback('#\{[^}]+\}#msi', 'remove_comments', $text);

var_dump($text);

function remove_comments($text) {
    return preg_replace('#/\*.*?\*/#msi', '', $text[0]);
}

?>

It searches for {} then removes the comments inside them. This will remove multiple comments in a {}.