dongweizhen2009 2012-03-05 00:33
浏览 38
已采纳

从mysql表加载的php代码在输出页面上没有解释

I am trying to make use of someone else's cms design as he stores his page content inside mysql table. i updated table manually and inserted following code:

<?php echo (int)$height ?>

Output page like said doesn't interpret code but rather displays it as a plain text.

This is how this guy fetch his content data:

echo html_entity_decode(stripcslashes(FetchFromTable("tbl_page","page_content","page_id", $_GET['page_id']))); 

Any help appreciated.

Thanks

  • 写回答

2条回答 默认 最新

  • duanfan8360 2012-03-05 00:37
    关注

    You can't put PHP code into the content of that CMS system. It doesn't support it.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥30 Unity接入微信SDK 无法开启摄像头
  • ¥20 有偿 写代码 要用特定的软件anaconda 里的jvpyter 用python3写
  • ¥20 cad图纸,chx-3六轴码垛机器人
  • ¥15 移动摄像头专网需要解vlan
  • ¥20 access多表提取相同字段数据并合并
  • ¥20 基于MSP430f5529的MPU6050驱动,求出欧拉角
  • ¥20 Java-Oj-桌布的计算
  • ¥15 powerbuilder中的datawindow数据整合到新的DataWindow
  • ¥20 有人知道这种图怎么画吗?
  • ¥15 pyqt6如何引用qrc文件加载里面的的资源