这是一个以％计算机会的好代码吗？

Question

Is this the right code to calculate a chance of 25%?

if(rand(1,100) < 25){
    echo 'succes';
}else{
    echo 'failed';
}

And if the chance for success should be 3,5%, I can change the 25 to 3.5?

Or is this better?

if (25 >= mt_rand(1,100)){
    echo 'succes';
}else{
    echo 'failed';
}

Answer 1

To be able to use rand() and use your method with one decimal value you can use the following:

if(rand(1, 1000) <= 35) {