preg_match_all从select选项中检索数据

Question

<select name="address_town" id="address_town" class="locationTown">
 <option value="#ANY">Empty</option>
 <option value="438" >First</option>
 <option value="420" >Second</option>
</select>

I want to retrieve data which are #ANY-Empty, 438-First and 420-Second I wrote a code but i could retrieve only first data. I want to all of them. My code is below:

preg_match_all('/<select[^>]+?address_town[^>]+?>(.*?)<\/select>/', $open, $matches);
$options = $matches[1];
foreach ($options as $select) {
    preg_match_all('/<option value="(.*?)">(.*?)<\/option>/', $select, $matches2);
}   
print_r($matches2);

Thanks for helping..

Answer 1

Firstly, at least in your example, the first preg_match_all is useless. Then to obtain the data you are asking simply do this :

preg_match_all('/<option value="(.*?)"\s*>(.*?)<\/option>/', $html, $matches, PREG_SET_ORDER);
foreach ($matches as $val) {
    echo $val[1].'-'.$val[2];
}

note that I added "\s*" after the value="" because you had spaces after it on some rows.

You may want to refer to the manual examples for more information http://php.net/manual/en/function.preg-match-all.php

EDIT: I didn't try running the code but this is the spirit :

preg_match_all('/<select[^>]+?address_town[^>]+?>(.*?)<\/select>/s', $open, $matches);
$options = $matches[1];
foreach ($options as $select) {
    preg_match_all('/<option value="(.*?)"\s*>(.*?)<\/option>/', $select, $matches, PREG_SET_ORDER);
    foreach ($matches as $val) {
        echo $val[1].'-'.$val[2].'
';
    }
}   

I added the s modifier at the end of the regexp so that the .* will accept the newline characters